Let's learn a bit about how Python keeps track of names
Namespaces are the way that Python organizes variable names
For example, suppose I write a script math2.py like this:
# Filename: math2.py
pi = 'foobar'
Now I start the Python interpreter and import it
>>> import math2
Next I import the math module from the standard library
>>> import math
Both of these modules have an attribute pi:
>>> math.pi
3.1415926535897931
>>> math2.pi
'foobar'
How is it that Python does not get confused with these two pi?
Whenever Python executes a module, it creates a namespace for that module
In Python, namespaces are implemented as dictionaries
We can look at the dictionary directly, using moduleName.__dict__:
>>> import math
>>> math.__dict__
{'pow': <built-in function pow>, ..., 'pi': 3.1415926535897931,...}
This namespace is created when we execute import math
When we access elements of the namespace using the dotted attribute notation
>>> math.pi
3.1415926535897931
this is in fact equivalent to math.__dict__['pi']
>>> math.__dict__['pi'] == math.pi
True
As we saw above, the math namespace can be printed by typing math.__dict__
Another way to see its contents is to type vars(math)
>>> vars(math)
{'pow': <built-in function pow>,...
Finally, if you just want to see the names, you can type
>>> dir(math)
['__doc__', '__file__', '__name__', 'acos', 'asin', 'atan',...
Notice the special names __doc__, __file__ and __name__
These are initialized in the namespace when any module is imported
__doc__ is the doc string of the module__file__ is the name of the file where the module code was read from__name__ is the name of the module>>> print math.__doc__
This module is always available. It provides access to the
mathematical functions defined by the C standard.
>>> math.__file__
'/usr/lib/python2.5/lib-dynload/math.so'
>>> math.__name__
'math'
In Python, commands typed at the prompt >>> are regarded as part of a module called __main__
An assignment such as
>>> x = 4
is stored in the namespace of __main__
To see the contents of __main__ use vars() rather than vars(__main__)
>>> vars() # After starting Python, before making any assignments
{'__builtins__': <module '__builtin__' (built-in)>,
'__name__': '__main__',
'__doc__': None}
Now let's make an assignment
>>> x = 4
>>> vars()
{'__builtins__': <module '__builtin__' (built-in)>,
'__name__': '__main__',
'__doc__': None,
'x': 4}
The variable x has been registered in the namespace
If we want to see just the names in __main__, we can use dir()
>>> dir()
['__builtins__', '__doc__', '__name__', 'x']
Next, suppose we have a file called mod1.py with the following code:
x = 3
def f():
pass # 'pass' means do nothing
To use this code, one option is to import it
>>> import mod1
In this case, the code in the script is regarded
as part of the module mod1.py
x and f are registered in the namespace of mod1mod1.x, mod1.fAnother option is to run it interactively
run mod1.pyRun ModuleIn this case, the code in the script is regarded as part of __main__
x and f are registered in namespace of __main__x rather than mod1.x, etc)Another way to see the difference between running as __main__ and importing:
Let's say we have a script mod2.py as follows
# Filename: mod2.py
print __name__
Now let's look at two different ways of running it in IPython
In [1]: import mod2 # Standard import
mod2
In [2]: run mod2.py # Run interactively
__main__
In the second case, the code is executed as part of __main__, so __name__ = '__main__'
Suppose we are working interactively, at the prompt >>>
When we import a module,
__main__>>> dir()
['__builtins__', '__doc__', '__name__']
>>> import math
>>> dir()
['__builtins__', '__doc__', '__name__', 'math']
math is created>>> dir(math)
['__doc__', '__file__', '__name__', 'acos', 'asin', 'atan',...
We can also import names directly into the current namespace using from
>>> from math import pi, e
>>> pi
3.1415926535897931
>>> e
2.7182818284590451
>>> dir()
['__builtins__', '__doc__', '__name__', 'e', 'math', 'pi']